This question was previously asked in

SSC MTS Previous Paper 1 (Held On: 2 August 2019 Shift 1)

Option 1 : 40/3 km/h

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Given

Distance1 = 15 km, Speed1 = 30 km/h

Distance2 = 25 km, Speed2 = 10 km/h

Formula Used:

Speed = Distance/Time

Average speed = Total distance/Total time

**Calculation:**

According to the question,

Total distance = 15 + 25 = 40 km

Total time = 15/30 + 25/10

⇒ (15 + 75)/30 = 90/30 = 3 hours

Average speed = 40/3 km/h

**∴ The average speed for the entire journey is 40/3 km/h.**

**Given **

D_{1} = 15 km, S_{1} = 30 km/h

D_{2} = 25 km, S_{2} = 10 km/h

**Formula Used:**

Average speed = \(\frac{{{D_1} + {D_2}}}{{\frac{{{D_1}}}{{{S_1}}} + \frac{{{D_2}}}{{{S_2}}}}}\)

**Calculation:**

Average speed for the entire journey = \(\frac{{15 + 25}}{{\frac{{15}}{{30}} + \frac{{25}}{{10}}}}\)

\(= \frac{{40}}{{0.5 + 2.5}}\)

\(= \frac{{40}}{3}\;km/h\)