Two isosceles triangles ΔABC and ΔDEF are similar. If BC = 15 cm, DE = 15 cm and EF = 9 cm and AB = AC and DE = DF, then find the sum of the perimeter of both the triangles.

- 89
- 96
- 104
- 112

Option 3 : 104

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**Given:** In isosceles ΔABC and isosceles ΔDEF,

BC = DE = 15 cm, EF = 9 cm

ΔABC ∼ ΔDEF

In isosceles ΔDEF,

⇒ DE = DF = 15 cm, EF = 9 cm

∵ ΔABC ∼ ΔDEF

⇒ AB/DE = BC/EF

⇒ AB/15 = 15/9

⇒ AB = 25 cm

In isosceles ΔABC,

AB = AC = 25 cm, BC = 15 cm

⇒ Sum of perimeter of both the triangles = (25 + 25 + 15) + (15 + 15 + 9) = 104 cm

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